24x^2-29x-4=0

Solution for 24x^2-29x-4=0 equation:

24x^2-29x-4=0

a = 24; b = -29; c = -4;
Δ = b2-4ac
Δ = -292-4·24·(-4)
Δ = 1225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1225}=35$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-29)-35}{2*24}=\frac{-6}{48}
=-1/8
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-29)+35}{2*24}=\frac{64}{48}
=1+1/3
$